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1/6x=2/3x=5
We move all terms to the left:
1/6x-(2/3x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/6x-(+2/3x)=0
We get rid of parentheses
1/6x-2/3x=0
We calculate fractions
3x/18x^2+(-12x)/18x^2=0
We multiply all the terms by the denominator
3x+(-12x)=0
We get rid of parentheses
3x-12x=0
We add all the numbers together, and all the variables
-9x=0
x=0/-9
x=0
Równanie nie ma rozwiązania
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