1/6q+1-3q=2-4q+1/8q

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Solution for 1/6q+1-3q=2-4q+1/8q equation:



1/6q+1-3q=2-4q+1/8q
We move all terms to the left:
1/6q+1-3q-(2-4q+1/8q)=0
Domain of the equation: 6q!=0
q!=0/6
q!=0
q∈R
Domain of the equation: 8q)!=0
q!=0/1
q!=0
q∈R
We add all the numbers together, and all the variables
1/6q-3q-(-4q+1/8q+2)+1=0
We add all the numbers together, and all the variables
-3q+1/6q-(-4q+1/8q+2)+1=0
We get rid of parentheses
-3q+1/6q+4q-1/8q-2+1=0
We calculate fractions
-3q+4q+8q/48q^2+(-6q)/48q^2-2+1=0
We add all the numbers together, and all the variables
q+8q/48q^2+(-6q)/48q^2-1=0
We multiply all the terms by the denominator
q*48q^2+8q+(-6q)-1*48q^2=0
We add all the numbers together, and all the variables
8q+q*48q^2+(-6q)-1*48q^2=0
Wy multiply elements
48q^3-48q^2+8q+(-6q)=0
We get rid of parentheses
48q^3-48q^2+8q-6q=0
We do not support eqpression: q^3

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