1/6p+8=-1/3p+18

Solution for 1/6p+8=-1/3p+18 equation:

1/6p+8=-1/3p+18

We move all terms to the left:

1/6p+8-(-1/3p+18)=0


Domain of the equation: 6p!=0

p!=0/6

p!=0

p∈R



Domain of the equation: 3p+18)!=0

p∈R


We get rid of parentheses

1/6p+1/3p-18+8=0

We calculate fractions


3p/18p^2+6p/18p^2-18+8=0

We add all the numbers together, and all the variables

3p/18p^2+6p/18p^2-10=0

We multiply all the terms by the denominator


3p+6p-10*18p^2=0

We add all the numbers together, and all the variables

9p-10*18p^2=0

Wy multiply elements

-180p^2+9p=0

a = -180; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-180)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-180}=\frac{-18}{-360}
=1/20
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-180}=\frac{0}{-360}
=0
$