1/6n*(n+1)*(n+2)=100

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Solution for 1/6n*(n+1)*(n+2)=100 equation: 



1/6n(n+1)(n+2)=100

We move all terms to the left:

1/6n(n+1)(n+2)-(100)=0



Domain of the equation: 6n(n+1)(n+2)!=0

n∈R



We multiply parentheses ..

1/6n(+n^2+2n+n+2)-100=0

We multiply all the terms by the denominator


-100*6n(+n^2+2n+n+2)+1=0

Wy multiply elements

-600n(++1=0

We use the square of the difference formula

-600n(+1=0

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