1/6b+2/3=1/4(b-2)

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Solution for 1/6b+2/3=1/4(b-2) equation: 



1/6b+2/3=1/4(b-2)

We move all terms to the left:

1/6b+2/3-(1/4(b-2))=0



Domain of the equation: 6b!=0

b!=0/6

b!=0

b∈R





Domain of the equation: 4(b-2))!=0

b∈R



We calculate fractions


(12bb/(72b^2b+(-(1*6b*3)/(72b^2b+192b^2/(72b^2b=0

We can not solve this equation

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