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1/6=-1/3(p+1)
We move all terms to the left:
1/6-(-1/3(p+1))=0
Domain of the equation: 3(p+1))!=0We calculate fractions
p∈R
()/18p+(3pp/18p=0
We multiply all the terms by the denominator
(3pp+()=0
We calculate terms in parentheses: +(3pp+(), so:p=0/1
3pp+(
We add all the numbers together, and all the variables
3pp
Back to the equation:
+(3pp)
p=0
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