1/6(x-5)=1/2(x+5)

Solution for 1/6(x-5)=1/2(x+5) equation:

1/6(x-5)=1/2(x+5)

We move all terms to the left:

1/6(x-5)-(1/2(x+5))=0


Domain of the equation: 6(x-5)!=0

x∈R



Domain of the equation: 2(x+5))!=0

x∈R


We calculate fractions


(2xx/(6(x-5)*2(x+5)))+(-6xx/(6(x-5)*2(x+5)))=0


We calculate terms in parentheses: +(2xx/(6(x-5)*2(x+5))), so:

2xx/(6(x-5)*2(x+5))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-6xx/(6(x-5)*2(x+5))), so:

-6xx/(6(x-5)*2(x+5))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)


We get rid of parentheses

2xx-6xx=0