1/6(x-5)=1/2(x+2)

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Solution for 1/6(x-5)=1/2(x+2) equation: 



1/6(x-5)=1/2(x+2)

We move all terms to the left:

1/6(x-5)-(1/2(x+2))=0



Domain of the equation: 6(x-5)!=0

x∈R





Domain of the equation: 2(x+2))!=0

x∈R



We calculate fractions


(2xx/(6(x-5)*2(x+2)))+(-6xx/(6(x-5)*2(x+2)))=0



We calculate terms in parentheses: +(2xx/(6(x-5)*2(x+2))), so:

2xx/(6(x-5)*2(x+2))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)





We calculate terms in parentheses: +(-6xx/(6(x-5)*2(x+2))), so:

-6xx/(6(x-5)*2(x+2))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

2xx-6xx=0

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