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1/6(x-26)=3+2x
We move all terms to the left:
1/6(x-26)-(3+2x)=0
Domain of the equation: 6(x-26)!=0We add all the numbers together, and all the variables
x∈R
1/6(x-26)-(2x+3)=0
We get rid of parentheses
1/6(x-26)-2x-3=0
We multiply all the terms by the denominator
-2x*6(x-26)-3*6(x-26)+1=0
Wy multiply elements
-12x^2(x-18x(x+1=0
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