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1/6(x-18)+(x+2)=x-4
We move all terms to the left:
1/6(x-18)+(x+2)-(x-4)=0
Domain of the equation: 6(x-18)!=0We get rid of parentheses
x∈R
1/6(x-18)+x-x+2+4=0
We multiply all the terms by the denominator
x*6(x-18)-x*6(x-18)+2*6(x-18)+4*6(x-18)+1=0
Wy multiply elements
6x^2(x-6x^2(x+12x(x+24x(x+1=0
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