1/6(n-3)=2/3(n+6)-1/3n

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Solution for 1/6(n-3)=2/3(n+6)-1/3n equation: 


n in (-oo:+oo)

(1/6)*(n-3) = (2/3)*(n+6)-((1/3)*n) // - (2/3)*(n+6)-((1/3)*n)

(1/6)*(n-3)-((2/3)*(n+6))+(1/3)*n = 0

(1/6)*(n-3)+(-2/3)*(n+6)+(1/3)*n = 0

1/6*(n-3)-2/3*(n+6)+n/3 = 0

(1/6*3*(n-3))/3+(-2/3*3*(n+6))/3+n/3 = 0

1/6*3*(n-3)-2/3*3*(n+6)+n = 0

n-3/2*n-27/2 = 0

-1/2*n-27/2 = 0

(-1/2*n-27/2)/3 = 0

(-1/2*n-27/2)/3 = 0 // * 3

-1/2*n-27/2 = 0

-1/2*n-27/2 = 0 // + 27/2

-1/2*n = 27/2 // : -1/2

n = 27/2/(-1/2)

n = -27

n = -27

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