1/6(n-1/8)=-2/3(n-i/2)

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Solution for 1/6(n-1/8)=-2/3(n-i/2) equation: 


x in (-oo:+oo)

(1/6)*(n-(1/8)) = (-2/3)*(n-(i/2)) // - (-2/3)*(n-(i/2))

(1/6)*(n-(1/8))-((-2/3)*(n-(i/2))) = 0

(1/6)*(n-1/8)+(2/3)*(n-(i/2)) = 0

1/6*(n-1/8)+2/3*(n-1/2*i) = 0

1/6*(n-1/8)+2/3*(n-1/2*i) = 0

5/6*n-1/3*i-1/48 = 0

5/6*n-1/3*i-1/48 = 0

x belongs to the empty set

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