1/6(b-4)=1/2b

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Solution for 1/6(b-4)=1/2b equation: 



1/6(b-4)=1/2b

We move all terms to the left:

1/6(b-4)-(1/2b)=0



Domain of the equation: 6(b-4)!=0

b∈R





Domain of the equation: 2b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

1/6(b-4)-(+1/2b)=0

We get rid of parentheses

1/6(b-4)-1/2b=0

We calculate fractions


2b/(12b^2-48b)+(-6bb/(12b^2-48b)=0



We calculate terms in parentheses: +(-6bb/(12b^2-48b), so:

-6bb/(12b^2-48b

We multiply all the terms by the denominator


-6bb

Back to the equation:

+(-6bb)



We get rid of parentheses

2b/(12b^2-48b)-6bb=0

We multiply all the terms by the denominator


2b-6bb*(12b^2-48b)=0

We multiply parentheses

-72b^3+288b^2+2b=0

We do not support ebpression: b^3

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