1/6(a-4)=1/3(2a+y)

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Solution for 1/6(a-4)=1/3(2a+y) equation: 


x in (-oo:+oo)

(1/6)*(a-4) = (1/3)*(2*a+y) // - (1/3)*(2*a+y)

(1/6)*(a-4)-((1/3)*(2*a+y)) = 0

(1/6)*(a-4)+(-1/3)*(2*a+y) = 0

1/6*(a-4)-1/3*(2*a+y) = 0

1/6*(a-4)-1/3*(2*a+y) = 0

-1/2*a-1/3*y-2/3 = 0

-1/2*a-1/3*y-2/3 = 0

x belongs to the empty set

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