1/6(a+3)=1/2(7-a)

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Solution for 1/6(a+3)=1/2(7-a) equation:



1/6(a+3)=1/2(7-a)
We move all terms to the left:
1/6(a+3)-(1/2(7-a))=0
Domain of the equation: 6(a+3)!=0
a∈R
Domain of the equation: 2(7-a))!=0
a∈R
We add all the numbers together, and all the variables
1/6(a+3)-(1/2(-1a+7))=0
We calculate fractions
(2a(-)/(6(a+3)*2(-1a+7)))+(-6aa/(6(a+3)*2(-1a+7)))=0
We calculate terms in parentheses: +(2a(-)/(6(a+3)*2(-1a+7))), so:
2a(-)/(6(a+3)*2(-1a+7))
We add all the numbers together, and all the variables
2a0/(6(a+3)*2(-1a+7))
We multiply all the terms by the denominator
2a0
We add all the numbers together, and all the variables
2a
Back to the equation:
+(2a)
We calculate terms in parentheses: +(-6aa/(6(a+3)*2(-1a+7))), so:
-6aa/(6(a+3)*2(-1a+7))
We multiply all the terms by the denominator
-6aa
Back to the equation:
+(-6aa)
We get rid of parentheses
2a-6aa=0

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