1/6(9-4)=1/3(2a+4)

Solution for 1/6(9-4)=1/3(2a+4) equation:

1/6(9-4)=1/3(2a+4)

We move all terms to the left:

1/6(9-4)-(1/3(2a+4))=0


Domain of the equation: 3(2a+4))!=0

a∈R


We add all the numbers together, and all the variables

-(1/3(2a+4))+1/65=0

We calculate fractions


()/390a+(3a2/390a=0

We multiply all the terms by the denominator


(3a2+()=0


We calculate terms in parentheses: +(3a2+(), so:

3a2+(

We add all the numbers together, and all the variables

3a^2

Back to the equation:

+(3a^2)


a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{6}=0$