1/6(7t-4)=t+3/3

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Solution for 1/6(7t-4)=t+3/3 equation:



1/6(7t-4)=t+3/3
We move all terms to the left:
1/6(7t-4)-(t+3/3)=0
Domain of the equation: 6(7t-4)!=0
t∈R
We add all the numbers together, and all the variables
1/6(7t-4)-(t+1)=0
We get rid of parentheses
1/6(7t-4)-t-1=0
We multiply all the terms by the denominator
-t*6(7t-4)-1*6(7t-4)+1=0
Wy multiply elements
-6t^2(7-6t(7+1=0

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