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1/6(5x+11)=2/3(2x-4)
We move all terms to the left:
1/6(5x+11)-(2/3(2x-4))=0
Domain of the equation: 6(5x+11)!=0
x∈R
Domain of the equation: 3(2x-4))!=0We calculate fractions
x∈R
(3x2/(6(5x+11)*3(2x-4)))+(-12x5/(6(5x+11)*3(2x-4)))=0
We calculate terms in parentheses: +(3x2/(6(5x+11)*3(2x-4))), so:
3x2/(6(5x+11)*3(2x-4))
We multiply all the terms by the denominator
3x2
We add all the numbers together, and all the variables
3x^2
Back to the equation:
+(3x^2)
We calculate terms in parentheses: +(-12x5/(6(5x+11)*3(2x-4))), so:
-12x5/(6(5x+11)*3(2x-4))
We multiply all the terms by the denominator
-12x5
We add all the numbers together, and all the variables
-12x^5
We do not support expression: x^5
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