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1/6(4x-1)=2/3-8x
We move all terms to the left:
1/6(4x-1)-(2/3-8x)=0
Domain of the equation: 6(4x-1)!=0
x∈R
Domain of the equation: 3-8x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-8x)!=-3
x!=-3/1
x!=-3
x∈R
1/6(4x-1)-(-8x+2/3)=0
We get rid of parentheses
1/6(4x-1)+8x-2/3=0
We calculate fractions
There is no solution for this equation
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