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1/6(3x-9)+52/3=2+1/3x
We move all terms to the left:
1/6(3x-9)+52/3-(2+1/3x)=0
Domain of the equation: 6(3x-9)!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/6(3x-9)-(1/3x+2)+52/3=0
We get rid of parentheses
1/6(3x-9)-1/3x-2+52/3=0
We calculate fractions
27x/(6(3x-9)*3x*3)+(-6x3/(6(3x-9)*3x*3)+(312x3/(6(3x-9)*3x*3)-2=0
We can not solve this equation
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