1/6(3x-)=1/8(4x+8)

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Solution for 1/6(3x-)=1/8(4x+8) equation: 



1/6(3x-)=1/8(4x+8)

We move all terms to the left:

1/6(3x-)-(1/8(4x+8))=0



Domain of the equation: 6(3x-)!=0

x∈R





Domain of the equation: 8(4x+8))!=0

x∈R



We add all the numbers together, and all the variables

1/6(+3x)-(1/8(4x+8))=0

We calculate fractions


(8x4/(6(+3x)*8(4x+8)))+(-6x0/(6(+3x)*8(4x+8)))=0



We calculate terms in parentheses: +(8x4/(6(+3x)*8(4x+8))), so:

8x4/(6(+3x)*8(4x+8))

We multiply all the terms by the denominator


8x4

We add all the numbers together, and all the variables

8x^4

We do not support expression: x^4

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