1/6(3x+2)=1/2(3x-8)

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Solution for 1/6(3x+2)=1/2(3x-8) equation: 



1/6(3x+2)=1/2(3x-8)

We move all terms to the left:

1/6(3x+2)-(1/2(3x-8))=0



Domain of the equation: 6(3x+2)!=0

x∈R





Domain of the equation: 2(3x-8))!=0

x∈R



We calculate fractions


(2x3/(6(3x+2)*2(3x-8)))+(-6x3/(6(3x+2)*2(3x-8)))=0



We calculate terms in parentheses: +(2x3/(6(3x+2)*2(3x-8))), so:

2x3/(6(3x+2)*2(3x-8))

We multiply all the terms by the denominator


2x3

We add all the numbers together, and all the variables

2x^3

We do not support expression: x^3

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