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1/6(3t-9)=t+9/12
We move all terms to the left:
1/6(3t-9)-(t+9/12)=0
Domain of the equation: 6(3t-9)!=0We add all the numbers together, and all the variables
t∈R
1/6(3t-9)-(+t+9/12)=0
We get rid of parentheses
1/6(3t-9)-t-9/12=0
We calculate fractions
There is no solution for this equation
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