1/6(3t-5)=11/6t-(t-5/12)

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Solution for 1/6(3t-5)=11/6t-(t-5/12) equation:


t in (-oo:+oo)

(1/6)*(3*t-5) = (11/6)*t-t+5/12 // - (11/6)*t-t+5/12

(1/6)*(3*t-5)-((11/6)*t)+t-(5/12) = 0

(1/6)*(3*t-5)+(-11/6)*t+t-5/12 = 0

1/6*(3*t-5)+(-11*t)/6+t-5/12 = 0

(1/6*6*12*(3*t-5))/(6*12)+(-11*12*t)/(6*12)+(6*12*t)/(6*12)+(-5*6)/(6*12) = 0

1/6*6*12*(3*t-5)-11*12*t+6*12*t-5*6 = 0

72*t-96*t-60-30 = 0

-24*t-60-30 = 0

-24*t-90 = 0

(-24*t-90)/(6*12) = 0

(-24*t-90)/(6*12) = 0 // * 6*12

-24*t-90 = 0

-24*t-90 = 0 // + 90

-24*t = 90 // : -24

t = 90/(-24)

t = -15/4

t = -15/4

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