1/6(36x-48)=1/8(32x+64)

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Solution for 1/6(36x-48)=1/8(32x+64) equation: 



1/6(36x-48)=1/8(32x+64)

We move all terms to the left:

1/6(36x-48)-(1/8(32x+64))=0



Domain of the equation: 6(36x-48)!=0

x∈R





Domain of the equation: 8(32x+64))!=0

x∈R



We calculate fractions


(8x3/(6(36x-48)*8(32x+64)))+(-6x3/(6(36x-48)*8(32x+64)))=0



We calculate terms in parentheses: +(8x3/(6(36x-48)*8(32x+64))), so:

8x3/(6(36x-48)*8(32x+64))

We multiply all the terms by the denominator


8x3

We add all the numbers together, and all the variables

8x^3

We do not support expression: x^3

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