1/6(12x+48)=-1/8(8x-16)+3x

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Solution for 1/6(12x+48)=-1/8(8x-16)+3x equation: 



1/6(12x+48)=-1/8(8x-16)+3x

We move all terms to the left:

1/6(12x+48)-(-1/8(8x-16)+3x)=0



Domain of the equation: 6(12x+48)!=0

x∈R





Domain of the equation: 8(8x-16)+3x)!=0

x∈R



We calculate fractions


(24x^2+64x)/(6(12x+48)*8(8x-16)+3x))+(-(-6x1)/(6(12x+48)*8(8x-16)+3x))=0



We calculate terms in parentheses: -(-6x1)/(6(12x+48)*8(8x-16)+3x)), so:

-6x1)/(6(12x+48)*8(8x-16)+3x)

We multiply all the terms by the denominator


-6x1)+3x)*(6(12x+48)*8(8x-16)

We add all the numbers together, and all the variables

-6x1)+3x)*(6(12x+48)*8(8x

Back to the equation:

-(-6x1)+3x)*(6(12x+48)*8(8x)



We add all the numbers together, and all the variables

(24x^2+64x)/(6(12x+48)*8(8x-16)+3x))+(-(-6x)+3x)*(6(12x+48)*88x=0

We get rid of parentheses

(24x^2+64x)/(6(12x+48)*8(8x-16)+3x))+(+6x+3x)*(6(12x+48)*88x=0

We multiply all the terms by the denominator


(24x^2+64x)+6x*(6(12x+48)*8(8x-16)+3x))+(+3x*(6(12x+48)*88x)*(6(12x+48)*8(8x-16)+3x))+(=0

We get rid of parentheses

24x^2+64x+6x*(6(12x+48)*8(8x-16)+3x))+(+3x*(6(12x+48)*88x)*(6(12x+48)*8(8x-16)+3x))+(=0

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