1/6(12h-18)=2h-3

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Solution for 1/6(12h-18)=2h-3 equation: 



1/6(12h-18)=2h-3

We move all terms to the left:

1/6(12h-18)-(2h-3)=0



Domain of the equation: 6(12h-18)!=0

h∈R



We get rid of parentheses

1/6(12h-18)-2h+3=0

We multiply all the terms by the denominator


-2h*6(12h-18)+3*6(12h-18)+1=0

Wy multiply elements

-12h^2(1+18h(1+1=0

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