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1/6(122-18)=2z-3
We move all terms to the left:
1/6(122-18)-(2z-3)=0
We add all the numbers together, and all the variables
-(2z-3)+1/6104=0
We get rid of parentheses
-2z+3+1/6104=0
We multiply all the terms by the denominator
-2z*6104+1+3*6104=0
We add all the numbers together, and all the variables
-2z*6104+18313=0
Wy multiply elements
-12208z+18313=0
We move all terms containing z to the left, all other terms to the right
-12208z=-18313
z=-18313/-12208
z=1+6105/12208
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