1/5z+.1=4/5z+.2

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Solution for 1/5z+.1=4/5z+.2 equation: 



1/5z+.1=4/5z+.2

We move all terms to the left:

1/5z+.1-(4/5z+.2)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R





Domain of the equation: 5z+.2)!=0

z∈R



We add all the numbers together, and all the variables

1/5z-(4/5z+0.2)+.1=0

We add all the numbers together, and all the variables

1/5z-(4/5z+0.2)+0.1=0

We get rid of parentheses

1/5z-4/5z-0.2+0.1=0

We multiply all the terms by the denominator


-(0.2)*5z+(0.1)*5z+1-4=0

We add all the numbers together, and all the variables

-(0.2)*5z+(0.1)*5z-3=0

We multiply parentheses

-z+0.5z-3=0

We add all the numbers together, and all the variables

-0.5z-3=0

We move all terms containing z to the left, all other terms to the right

-0.5z=3

z=3/-0.5

z=-6

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