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1/5y=3
We move all terms to the left:
1/5y-(3)=0
Domain of the equation: 5y!=0We multiply all the terms by the denominator
y!=0/5
y!=0
y∈R
-3*5y+1=0
Wy multiply elements
-15y+1=0
We move all terms containing y to the left, all other terms to the right
-15y=-1
y=-1/-15
y=1/15
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