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1/5x=10x-120
We move all terms to the left:
1/5x-(10x-120)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/5x-10x+120=0
We multiply all the terms by the denominator
-10x*5x+120*5x+1=0
Wy multiply elements
-50x^2+600x+1=0
a = -50; b = 600; c = +1;
Δ = b2-4ac
Δ = 6002-4·(-50)·1
Δ = 360200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360200}=\sqrt{100*3602}=\sqrt{100}*\sqrt{3602}=10\sqrt{3602}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-10\sqrt{3602}}{2*-50}=\frac{-600-10\sqrt{3602}}{-100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+10\sqrt{3602}}{2*-50}=\frac{-600+10\sqrt{3602}}{-100} $
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