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x in (-oo:+oo)
(1/5)*x = (1/5)*x+5 // - (1/5)*x+5
(1/5)*x-((1/5)*x)-5 = 0
(1/5)*x+(-1/5)*x-5 = 0
-5 = 0
x belongs to the empty set
x belongs to the empty set
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