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1/5x-5=9-1/2x
We move all terms to the left:
1/5x-5-(9-1/2x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(-1/2x+9)-5=0
We get rid of parentheses
1/5x+1/2x-9-5=0
We calculate fractions
2x/10x^2+5x/10x^2-9-5=0
We add all the numbers together, and all the variables
2x/10x^2+5x/10x^2-14=0
We multiply all the terms by the denominator
2x+5x-14*10x^2=0
We add all the numbers together, and all the variables
7x-14*10x^2=0
Wy multiply elements
-140x^2+7x=0
a = -140; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-140)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-140}=\frac{-14}{-280} =1/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-140}=\frac{0}{-280} =0 $
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