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1/5x-50=2x-5
We move all terms to the left:
1/5x-50-(2x-5)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/5x-2x+5-50=0
We multiply all the terms by the denominator
-2x*5x+5*5x-50*5x+1=0
Wy multiply elements
-10x^2+25x-250x+1=0
We add all the numbers together, and all the variables
-10x^2-225x+1=0
a = -10; b = -225; c = +1;
Δ = b2-4ac
Δ = -2252-4·(-10)·1
Δ = 50665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-\sqrt{50665}}{2*-10}=\frac{225-\sqrt{50665}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+\sqrt{50665}}{2*-10}=\frac{225+\sqrt{50665}}{-20} $
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