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1/5x-2=x-1
We move all terms to the left:
1/5x-2-(x-1)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/5x-x+1-2=0
We multiply all the terms by the denominator
-x*5x+1*5x-2*5x+1=0
Wy multiply elements
-5x^2+5x-10x+1=0
We add all the numbers together, and all the variables
-5x^2-5x+1=0
a = -5; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·(-5)·1
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3\sqrt{5}}{2*-5}=\frac{5-3\sqrt{5}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3\sqrt{5}}{2*-5}=\frac{5+3\sqrt{5}}{-10} $
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