1/5x+7/5x=40

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Solution for 1/5x+7/5x=40 equation:



1/5x+7/5x=40
We move all terms to the left:
1/5x+7/5x-(40)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We multiply all the terms by the denominator
-40*5x+1+7=0
We add all the numbers together, and all the variables
-40*5x+8=0
Wy multiply elements
-200x+8=0
We move all terms containing x to the left, all other terms to the right
-200x=-8
x=-8/-200
x=1/25

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