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1/5x+3/4=5-1/4x
We move all terms to the left:
1/5x+3/4-(5-1/4x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(-1/4x+5)+3/4=0
We get rid of parentheses
1/5x+1/4x-5+3/4=0
We calculate fractions
64x/320x^2+5x/320x^2+15x/320x^2-5=0
We multiply all the terms by the denominator
64x+5x+15x-5*320x^2=0
We add all the numbers together, and all the variables
84x-5*320x^2=0
Wy multiply elements
-1600x^2+84x=0
a = -1600; b = 84; c = 0;
Δ = b2-4ac
Δ = 842-4·(-1600)·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-84}{2*-1600}=\frac{-168}{-3200} =21/400 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+84}{2*-1600}=\frac{0}{-3200} =0 $
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