1/5x+3+4x-2=(1/2x+6)(5)

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Solution for 1/5x+3+4x-2=(1/2x+6)(5) equation:


x in (-oo:+oo)

(1/5)*x+4*x-2+3 = 5*((1/2)*x+6) // - 5*((1/2)*x+6)

(1/5)*x-(5*((1/2)*x+6))+4*x-2+3 = 0

(1/5)*x-5*((1/2)*x+6)+4*x-2+3 = 0

x/5-5*(1/2*x+6)+4*x-2+3 = 0

(-5*5*(1/2*x+6))/5+x/5+(4*5*x)/5+(-2*5)/5+(3*5)/5 = 0

x-5*5*(1/2*x+6)+4*5*x-2*5+3*5 = 0

20*x-23/2*x-150-10+15 = 0

17/2*x-150-10+15 = 0

17/2*x-160+15 = 0

17/2*x-145 = 0

(17/2*x-145)/5 = 0

(17/2*x-145)/5 = 0 // * 5

17/2*x-145 = 0

17/2*x-145 = 0 // + 145

17/2*x = 145 // : 17/2

x = 145/17/2

x = 290/17

x = 290/17

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