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1/5x+2=3-(2/7)
We move all terms to the left:
1/5x+2-(3-(2/7))=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x+2-(3-(+2/7))=0
We calculate fractions
()/35x^2+(-(3-(+2*5x)/35x^2+2=0
We calculate fractions
We do not support expression: x^4
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