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1/5x+1/x=3
We move all terms to the left:
1/5x+1/x-(3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
x/5x^2+5x/5x^2-3=0
We multiply all the terms by the denominator
x+5x-3*5x^2=0
We add all the numbers together, and all the variables
6x-3*5x^2=0
Wy multiply elements
-15x^2+6x=0
a = -15; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-15)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-15}=\frac{-12}{-30} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-15}=\frac{0}{-30} =0 $
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