1/5x+1/4x=16

Solution for 1/5x+1/4x=16 equation:

1/5x+1/4x=16

We move all terms to the left:

1/5x+1/4x-(16)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


4x/20x^2+5x/20x^2-16=0

We multiply all the terms by the denominator


4x+5x-16*20x^2=0

We add all the numbers together, and all the variables

9x-16*20x^2=0

Wy multiply elements

-320x^2+9x=0

a = -320; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-320)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-320}=\frac{-18}{-640}
=9/320
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-320}=\frac{0}{-640}
=0
$