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1/5t-8=2
We move all terms to the left:
1/5t-8-(2)=0
Domain of the equation: 5t!=0We add all the numbers together, and all the variables
t!=0/5
t!=0
t∈R
1/5t-10=0
We multiply all the terms by the denominator
-10*5t+1=0
Wy multiply elements
-50t+1=0
We move all terms containing t to the left, all other terms to the right
-50t=-1
t=-1/-50
t=1/50
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