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1/5q=9+2/5q
We move all terms to the left:
1/5q-(9+2/5q)=0
Domain of the equation: 5q!=0
q!=0/5
q!=0
q∈R
Domain of the equation: 5q)!=0We add all the numbers together, and all the variables
q!=0/1
q!=0
q∈R
1/5q-(2/5q+9)=0
We get rid of parentheses
1/5q-2/5q-9=0
We multiply all the terms by the denominator
-9*5q+1-2=0
We add all the numbers together, and all the variables
-9*5q-1=0
Wy multiply elements
-45q-1=0
We move all terms containing q to the left, all other terms to the right
-45q=1
q=1/-45
q=-1/45
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