If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5m-2=m-2/5
We move all terms to the left:
1/5m-2-(m-2/5)=0
Domain of the equation: 5m!=0We add all the numbers together, and all the variables
m!=0/5
m!=0
m∈R
1/5m-(+m-2/5)-2=0
We get rid of parentheses
1/5m-m-2+2/5=0
We calculate fractions
-m-2=0
We add all the numbers together, and all the variables
-1m-2=0
We move all terms containing m to the left, all other terms to the right
-m=2
m=2/-1
m=-2
| 5p+3=2(2p-3)-2(4-p) | | 2p=8-2p | | z+7/3=8 | | j-14=-9 | | 3.5=7.7-0.6x | | X=4+5i | | -4t=6-5t | | 303-j=125 | | 56q=-91q+3(20q+29) | | 5x-4+5x-4=8x+4 | | 17+3c=38 | | X=5-4i | | 3=s/4-3 | | 17k-7k+2=12 | | 6x-15=10x+18 | | 21+7n=49 | | 82=25+3j | | 3(x+1)=2x+25-1 | | 7g-26=37 | | X+7=5x+10 | | r+30/3=2 | | 16=4(p-14) | | 26=5(p−5)+6 | | 4(1-x)+3x=-x=1) | | 26+6m=74 | | 6c+-9c=15 | | 2-4(m-1)=-4m+11 | | j/6+-10=-17 | | 11+5p=21 | | 30-8=13-3p | | 37.35=8g+3.51 | | 31=3x |