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1/5-x+3=5/2+x
We move all terms to the left:
1/5-x+3-(5/2+x)=0
Domain of the equation: 2+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-2
x!=-2/1
x!=-2
x∈R
-x-(+x+5/2)+3+1/5=0
We add all the numbers together, and all the variables
-1x-(+x+5/2)+3+1/5=0
We get rid of parentheses
-1x-x+3-5/2+1/5=0
We calculate fractions
There is no solution for this equation
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