1/5+(3/5x)-2/x

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Solution for 1/5+(3/5x)-2/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/5)*x-(2/x)+1/5 = 0

(3/5)*x-2*x^-1+1/5 = 0

3/5*x^1-2*x^-1+1/5*x^0 = 0

(3/5*x^2+1/5*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(3/5*x^2+1/5*x^1-2*x^0) = 0

x^1

(3/5)*x^2+(1/5)*x-2 = 0

(3/5)*x^2+(1/5)*x-2 = 0

DELTA = (1/5)^2-(-2*4*(3/5))

DELTA = 121/25

DELTA > 0

x = ((121/25)^(1/2)-(1/5))/(2*(3/5)) or x = (-(1/5)-(121/25)^(1/2))/(2*(3/5))

x = 5/3 or x = -2

x in { -2, 5/3} 

x in { -2, 5/3 }

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