1/5(y-3)=1/6(y+4)

Solution for 1/5(y-3)=1/6(y+4) equation:

1/5(y-3)=1/6(y+4)

We move all terms to the left:

1/5(y-3)-(1/6(y+4))=0


Domain of the equation: 5(y-3)!=0

y∈R



Domain of the equation: 6(y+4))!=0

y∈R


We calculate fractions


(6yy/(5(y-3)*6(y+4)))+(-5yy/(5(y-3)*6(y+4)))=0


We calculate terms in parentheses: +(6yy/(5(y-3)*6(y+4))), so:

6yy/(5(y-3)*6(y+4))

We multiply all the terms by the denominator


6yy

Back to the equation:

+(6yy)



We calculate terms in parentheses: +(-5yy/(5(y-3)*6(y+4))), so:

-5yy/(5(y-3)*6(y+4))

We multiply all the terms by the denominator


-5yy

Back to the equation:

+(-5yy)


We get rid of parentheses

6yy-5yy=0