1/5(y+2)=4

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Solution for 1/5(y+2)=4 equation: 



1/5(y+2)=4

We move all terms to the left:

1/5(y+2)-(4)=0



Domain of the equation: 5(y+2)!=0

y∈R



We multiply all the terms by the denominator


-4*5(y+2)+1=0

Wy multiply elements

-20y(y+1=0

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