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1/5(x-7)=1+3x
We move all terms to the left:
1/5(x-7)-(1+3x)=0
Domain of the equation: 5(x-7)!=0We add all the numbers together, and all the variables
x∈R
1/5(x-7)-(3x+1)=0
We get rid of parentheses
1/5(x-7)-3x-1=0
We multiply all the terms by the denominator
-3x*5(x-7)-1*5(x-7)+1=0
Wy multiply elements
-15x^2(x-5x(x+1=0
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