1/5(x-3)=1/6(x+4)

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Solution for 1/5(x-3)=1/6(x+4) equation: 



1/5(x-3)=1/6(x+4)

We move all terms to the left:

1/5(x-3)-(1/6(x+4))=0



Domain of the equation: 5(x-3)!=0

x∈R





Domain of the equation: 6(x+4))!=0

x∈R



We calculate fractions


(6xx/(5(x-3)*6(x+4)))+(-5xx/(5(x-3)*6(x+4)))=0



We calculate terms in parentheses: +(6xx/(5(x-3)*6(x+4))), so:

6xx/(5(x-3)*6(x+4))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-5xx/(5(x-3)*6(x+4))), so:

-5xx/(5(x-3)*6(x+4))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

6xx-5xx=0

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